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Determine the total energy loss:
Two capacitors C1 = 50 μF and C2 = 100 μF are connected in parallel across 250 V supply. Determine the total energy loss.
Figure
Total capacitance C = C1 + C2
= 50 + 100 = 150 μF
Energy loss =( ½) Cv2
=( 1 /2)(150 × 10- 6 ) (250)2 = 4.687 joules
Control Strategies Equation shows that output voltage V0 can be controlled through α and this duty cycle α can be varied by various strategies which are as follows.
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