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Q. Mrs. Cooper asked her math class to keep track of their own grade. Michael, one of the students, lost his assignments, but he remembered the grades of 6 out of 8 assignments: 93, 65, 70, 68, 62 and 84. He also remembered that the mean of his grades for all 8 assignments was 73 and the other two assignments had identical grades. What were the grades on Michael's other two assignments?
Solution:
Let x be the grade for each of the two missing assignments. Since Michael knows the mean of all 8 assignments is 73, we have:
The missing grades were both 71.
Special Forms There are a number of nice special forms of some polynomials which can make factoring easier for us on occasion. Following are the special forms. a 2 + 2ab +
reflection
find the equation to the sphere through the circle xsqaure+ysquare+zsquare+=9 , 2x+3y+4z=5
compare: 643,251: 633,512: 633,893. The answer is 633,512.
The two sides of a triangle are 17 cm and 28 cm long, and the length of the median drawn to the third side is equal to 19.5 cm. Find the distance from an endpoint of this median to
A bricklayer estimates that he requires 6.5 bricks per square foot. He needs to lay a patio that will be 110 square feet. How many bricks will he required? Multiply 6.5 by 110;
tan^2=(secx-1)(secx+1)
students dont retain the topic, hoe to make it easier?
from 0->1: Int sqrt(1-x^2) Solution) I=∫sqrt(1-x 2 )dx = sqrt(1-x 2 )∫dx - ∫{(-2x)/2sqrt(1-x 2 )}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x 2 ) - ∫-x 2 /√(1-x 2 ) Let
8+2=
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