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A motor has an output of 4.8kW, an efficiency of 80% and a power factor of 0.625 lagging when operated from a 240V, 50Hz supply.
It is needed to improve the power factor to 0.95 lagging by connecting a capacitor in parallel with the motor.
Determine
(a) The current taken by the motor,
(b) The supply current after power factor correction,
(c) The current taken by the capacitor,
(d) The capacitance of the capacitor, and
(e) The kvar rating of the capacitor.
Can you please, explain what is ''n'' in this equation: Q=ne?
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