Determine Potential Difference:

Compute the current through each element of the given network and also determine potential difference across 15 Ω resistor.

Figure

Solution

The circuit may be reduced in the following form :

Figure

Total current i in the circuit is achieved by

 i = V/ R = 100 /(5 + 10 + 6) = 100 /21= 4.76 Amp

So the current through 5 Ω and 10 Ω resistor shall be i = 4.76 Amp.

Now, current through 10 Ω resistor in parallel branch is find out by current division rule :

i₁ = i × (r₂ / (r₁ + r₂))

= 4.76 × (15 / (10 + 15)) = 2.85 Amp

Likewise, current through 15 Ω resistor is

i₂  = i × (10 / (r₁ + r₂))

= 4.76 × (10 /(10 + 15))

= 1.9 Amp

∴Potential difference across 15 Ω resistor shall be

 V = i₂  × 15= 1.9 × 15 = 28.5 volts