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Determine a normalized frequency at 820nm for a step index fibre having 25µm core radius. Given n1=1.48 and n2=1.46.Also calculate how several modes propagate within this fibre at 820nm.
Normalized frequency,
f = c/λ
Substituting c=3 x 108 m/s
Λ= 820nm
f = 3.658 x 1014 Hz
Given n1=1.48
n2=1.46
r = 25µm
We have
V= Πd (n12- n22)½ / λ
Substituting the values, we get
V=46.45
Take V=46
No. of modes= V2/2 =462/2 = 1058
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