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Remember that a graph will have a y-intercept at the point (0, f (0)) . Though, in this case we have to ignore x = 0 and thus this graph will never cross the y-axis. It does get extremely close to the y-axis, but it will never cross or touch it & thus no y-intercept.
Next, remember that we can determine where a graph will have x-intercepts by solving f ( x ) = 0 .
For rational functions this might seem like a mess to deal along with. Though, there is a nice fact regarding rational functions which we can use here. A rational function will be zero at a specific value of x only if the numerator is zero at that x & the denominator isn't zero at that x. In other terms, to determine if a rational function is ever zero all that we need to do is set the numerator equal to zero & solve. Once we have these solutions we just need to check that none of them make the denominator zero as well.
In our case the numerator is one and will never be zero and so this function will have no x- intercepts. Again, the graph will get extremely close to the x-axis but it will never touch or cross it.
At last, we have to address the fact that graph gets extremely close to the x and y-axis but never crosses. Since there isn't anything special about the axis themselves we'll use the fact that the x- axis is actually the line specified by y =0 and the y-axis is really the line specified by x = 0.
Working together Jack and Bob can clean a place in 30 minutes. On his own, Jack can clean this place in 50 minutes. How long does it take Bob to clean the same place on his own?
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I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)
YOU EARN 15N DOLLARS FOR MOWING N LAWNS.HOW MUCH DO YOU EARN FOR MOWING ONE LAWN? SEVEN LAWNS?
in the year 2000, radio stations numbered 220. The number of stations has since increased by approximatly 14.3% per year. Let x represent the number of years since 2000,and y repre
how do you solve a equation
a^2-b^2-c^2-2bc
|60-10*5|-11|2-16|
i need help on my homework could u help me ?
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