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A depth-first traversal of a tree visits a nodefirst and then recursively visits the subtrees of that node. Similarly, depth-first traversal of a graph visits a vertex and then recursively visits all the vertices adjoining to that node. The catch is that the graph may contain cycles, but the traversal must visit each vertex at most once. The solution to the problem is to keep track of the nodes that have been visited, so that the traversal does not experience the fate of infinite recursion.
explain collision resloving techniques in hasing
Generally, Computational complexity of algorithms are referred to through space complexity (space needed for running program) and time complexity (time needed for running the progr
A graph is a mathematical structure giving of a set of vertexes (v1, v2, v3) and a group of edges (e1, e2, e3). An edge is a set of vertexes. The two vertexes are named the edge en
Open addressing The easiest way to resolve a collision is to start with the hash address and do a sequential search by the table for an empty location.
how can i delete from deque while deletion is restricted from one end
Q. Can a Queue be represented by circular linked list with only one pointer pointing to the tail of the queue? Substantiate your answer using an example. A n s . Yes a
A graph with n vertices will absolutely have a parallel edge or self loop if the total number of edges is greater than n-1
The space-complexity of the algorithm is a constant. It just needs space of three integers m, n and t. Thus, the space complexity is O(1). The time complexity based on the loop
ESO207: Programming Assignment 1 Due on 6 Sept, 2015. To be submitted online. Problem In this assignment you are required to implement k-way Merge Sort algorithm. In this version p
3. A function to convert a complex number in algebraic form to a complex number in phasor form
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