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Process:
pid
start time
end time
priority
timeslice
list of CPU bursts
list of IO bursts (the number of IO burst will always be 1 less than the number of CPU bursts)
Start up Queue:
holds the processes which have not started executing (start time > clock)
(recommendation: order by start time)
Active/Expired Queue:
holds the processes that are waiting to use the cpu
(recommendation: order by priority)
IO Queue:
holds processes that are currently waiting for IO burst to finish.
(recommendation: order by current io burst left)
Finished Queue:
holds the processes that have completed all its cpu bursts
(recommendation: order by finish time)
CPU:
holds the process that is currently executing in the cpu.
MsgBox is a built in VB function which shows a Message Box and MsgBoxQ is a function definite by the user.
Explain the key characteristics of mobile computing applications
How to Creating a Key Pair You can make a key pair using the Strong Name tool (Sn.exe). Key pair files usually have an .snk extension. To create a key pair at the command
Simulated Annealing: One way to get around the problem of local maxima, and related problems like ridges and plateaux in hill climbing is to allow the agent to go downhill to
Not at this time. With GIMP based on GEGL, so that all changes are non-destructive, it will be much easier to execute this feature by just remembering all nodes in given range and
General purpose register - assembly language: Basic ISA Classes: Accumulator: 1 address add Aacc ←acc + mem [A] Stack: 0 address add to s ←to s+ next G
Evaluation Functions: Evaluation functions calculate approximately the score which can be prove of guaranteed if a particular world state is reached. Same like in chess, evalu
explain in RAID
The next major set of tasks to tackle are delete and update. Version control systems typically version updates to a ?le and only store the differences between the ?les. Two system
Simplified the Boolean Algebra (x + y)(x + z) simplifies to ? Ans. x + yz as simplified the Boolean Algebra expression. [(x + y) (x + z)] = xx + xz + xy + yz = x + xz + xy + y
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