Data phases - computer architecture, Computer Engineering

Assignment Help:

Data phases:

After the address phase (particularly, starting with the cycle that DEVSEL# goes low) comes a burst of one or more data phases. In all the cases, initiator drives active-low byte choose signals on the C/BE[3:0]# lines, however the data on the AD[31:0] may be driven by the initiator (on case of writes) or target (in case of reads).

During data phases, the C/BE [3:0] # lines are interpreted as active-low byte enables. In case of a write, the asserted signals indicate which of the four bytes on the AD bus are to be written to the addressed location. In the case of a read, they specify which bytes the initiator is interested in. For reads, it is always permissible to ignore the byte enable signals and simply return all 32 bits; cacheable memory resources are needed to always return 32 valid bits. The byte enables are chiefly useful for I/O space accesses where reads have side effects.

A data phase with all 4 C/BE# lines deserted is explicitly allowed by the PCI standard, and must have no effect on the target (other than to advance the address in the burst access in progress).

The data phase continues till both parties are ready to complete the transfer and continue to the next data phase. The initiator asserts the IRDY# (initiator is ready) when it no longer required to wait, whereas the target asserts TRDY# (target ready). Whichever side is providing the data have to drive it on the AD bus before asserting its ready signal.

Once one of the contributors asserts its ready signal, this cannot become un-ready or otherwise alter its control signals till the end of the data phase. The data recipient have to latch the AD bus each cycle till it sees IRDY# and TRDY#  both asserted, which marks the end of the current data phase and mention that the just -latched data is the word to be transferred.

To maintain complete burst speed, the data sender then has half a clock cycle after seeing TRDY# and IRDY# both asserted to drive the next word onto the AD bus.

It continues the address cycle shown above, supposing a single address cycle having medium DEVSEL, so the target responds for clock 3in time. Though, at that time, neither side is ready to transfer data. For clock 4, initiator is ready to transfer, but the target is not ready. On clock 5, both are ready, and a data transfer takes place (as mention by the vertical lines). For clock 6, the target is ready to transfer, but the initiator is not ready. On clock 7, the initiator becomes ready, and then data is transferred. For clocks 8 and 9, both sides remain ready to transfer data and transferred it at the maximum possible rate (32 bits per clock cycle).

In particular case of a read, clock 2 is reserved for turning around the AD bus, so the target is not allowed to drive data on the bus even if it is capable of fast DEVSEL.

Fast DEVSEL# on reads

A target that supports fast DEVSEL could in theory start responding to a read the cycle after the address is existing. However, this particular cycle is reserved for AD bus turnaround. Therefore, a target may not drive the AD bus (and therefore may not assert TRDY#) on the second cycle of a transaction. Notice that most of the targets will not be this type of fast and will not require any special logic to enforce this condition.


Related Discussions:- Data phases - computer architecture

Copy machine problem, We are trying to figure out how many copy machines we...

We are trying to figure out how many copy machines we should install in the basement of Stranahan Hall.  Copy machines should be available 24/7.  Students may walk up at any time o

In which network configuration all data/information pass, A distributed net...

A distributed network configuration in which all data/information pass through a central computer is (A)  Bus network                            (B) Star network (C)  Rin

Algorithem, for calculating simple interest

for calculating simple interest

What do you meant by a multimedia authoring system, Problem : a) What d...

Problem : a) What do you meant by a Multimedia Authoring System? b) Compare the verbose syntax to the dot syntax in Lingo. c) Explain each of the following terms: i) L

Network topology, According to the report, network 1 and network 2 are not ...

According to the report, network 1 and network 2 are not able to reach network 3. As shown on OTBNetwork Topology above, OTB Inc. has 2 routing protocols running due transition iss

Callable modules of program code within one abap/4 program, How can we crea...

How can we create callable modules of program code within one ABAP/4 program? We can create callable modules by two techniques:- By defining Macros. By creating incl

Define addressing modes, Define addressing modes. The dissimilar ways i...

Define addressing modes. The dissimilar ways in which the location of an operand is specified in an instruction are referred to as addressing modes.

Explain the matlab language, This is a high-level matrix/array language wit...

This is a high-level matrix/array language with control flow statements, functions, data structures, input/output, and object-oriented programming features. It permits both "progra

Define thread cancellation and target thread, Define thread cancellation & ...

Define thread cancellation & target thread.  The thread cancellation is the task of terminating a thread before it has done. A thread that is to be cancelled is often referred

Advantage of booth and restoring division algorithm, Describe the advantage...

Describe the advantage of using Booth algorithm? Ans:  a) It achieves efficiency in the number of additions needed when the multiplier has a few large blocks of 1's. b) It

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd