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Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x3 . Really there isn't much to do here other than only plugging in some points & plotting.
x
f(x)
0
1
-1
2
8
-2
-8
Following is graph of this function.
I need help in solving this problem: x^2-12+27
Properties of f( x ) = b x 1. The graph of f( x ) will always have the point (0,1). Or put another way, f(0) = 1 in spite of of the value of b. 2. For every possible b b x
how to graph f(x)=-x to the 3rd minus 3 using transformations
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What is ALgebra
2x-3y=2 5x+4y=28
4 pipes can fill a tank in 70 minutes.how long will it take to fill the tank by 7 pipes
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Vertical asymptote In our graph as the value of x approaches x = 0 the graph begin gets extremely large on both sides of the line given by x = 0. This line is called a vertical
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