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Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x3 . Really there isn't much to do here other than only plugging in some points & plotting.
x
f(x)
0
1
-1
2
8
-2
-8
Following is graph of this function.
y^2+3y+2=0
How do I figure out what is 20% of 100?
-1 1/2+ v = -3 3/10
solve on graph y y>(=)4x+1
Properties of f( x ) = b x 1. The graph of f( x ) will always have the point (0,1). Or put another way, f(0) = 1 in spite of of the value of b. 2. For every possible b b x
37/K^2-K-30
How do I do this?? x/x+1=x/2(x-4)
6x^3+3x^2-18x
Next we desire to take a look at f (x ) =√x . First, note that as we don't desire to get complex numbers out of a function evaluation we ought to limit the values of x that we can
what is quarditic equation
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