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Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x3 . Really there isn't much to do here other than only plugging in some points & plotting.
x
f(x)
0
1
-1
2
8
-2
-8
Following is graph of this function.
Example Evaluate following logarithms. log 4 16 Solution Now, the reality is that directly evaluating logarithms can be a very complicated process, even for those who
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M-(-14)=-7
p(x)=x-a
x2 -x = 7 -3 -5 1 5 -3
are these like terms
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