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Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x3 . Really there isn't much to do here other than only plugging in some points & plotting.
x
f(x)
0
1
-1
2
8
-2
-8
Following is graph of this function.
How can x raised to the second power mines x mines 2 . can be factored as (x+1)(x-2)
$2.350 is invested in account paying 9% compound semiannually. how much will the account be worth after 8yrs
Example : Solve (x+ 1 / x - 5 )≤ 0 . Solution Before we get into solving these we need to point out that these don't solve in the similar way which we've solve equations
In a yacht race the second leg was half the length of the first leg, the third leg was two-thirds of the second leg, and the last leg was twice the length of the second leg. If the
2x-1=10 I got 9/2 but i''m not sure if that is really right
7x to the 2 power y -9x to the 2 power y-2x to the 2 power y
we are going to fence into a rectangular field & we know that for some cause we desire the field to have an enclosed area of 75 ft2. We also know that we desire the width of the fi
x+6=2x+2
(2+x)+y=2+(x+y)
point a
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