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Actually here we're not going to look at a general cubic polynomial. Here we are jsut going to look at f ( x ) = x3 . Really there isn't much to do here other than only plugging in some points & plotting.
x
f(x)
0
1
-1
2
8
-2
-8
Following is graph of this function.
I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)
w2+30w+81 need step by step and explanation.
(3x+2y+2z) + (3x+5y+3z)
can you explain to me how to solve x^3+x+5
These are the only possibilities for solving quadratic equations in standard form. However Note that if we begin with rational expression in the equation we might get different so
if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
Sketch the graph parabolas. g ( x ) = 3x 2 - 6 x + 5 Solution For this parabola we've obtain a = 3 , b = -6 and c = 5 . Ensure that you're cautious with signs while id
2x^3+y+x+2x^2y
Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is. 1. Determine the vertex. We'll discus
Kevin randomly selected 1 card from a Standard deck of 52 cards. what is the probabilty that he will get the king of hearts?? Multiple choice .... 4/13.... 17/52...... 13/4..... 5
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