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In coordination compounds , how to decide whether itss hybridisation will be sp3d2 or d2sp3.. itss based on inner or outer orbital complex but how will we got to know that for every compound ..plzz explain..?Ans) In sp3d2 all s,p and d orbitals are from the same energy level. But in d2sp3, d orbital is from (n-1)th energy level.
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The electronic configuration of element with atomic number 24 is : (1) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 4 4s 2 (2) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 (3)
Which of the following set of quantum numbers is possible: (1) n=3, l=2, m=2,and s = +1/2 (2) n=3, l=4, m=0,and s = -1/2 (3) n=3, l=2, m=2,and s = +1/2 (4
An example for trihydric phenols
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Q. What do you mean by Dehydration? The word dehydration usually refers to the use of controlled conditions of heating, with the forced circulation of air/artificial dryer as
Explain terminal carbons and central carbons The terminal carbons are bound to three groups, and are thus trigonal planar. The central carbon is bound to two groups, and is
A 15 m 3 tank contains steam at 10 bar and 300 o C. The system is then cooled until the temperature reaches 150 o C . Some of the steam condenses. a) How much heat was transf
GROUP 2: ALKALINE EARTHS The elements known commonly as alkaline earths have atoms with the (ns) 2 design and almost always have the +2 oxidation state in their compound
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The hybridisation of coordination compounds is based on valence bond theory.. if the metal in the coordinate sphere is linked to strong ligands (for e.g. CN-) then the electrons of (n-1)d orbital pair up against hund''''s rule and the vacant spaces therefore formed is used up to combine with the ligands.. this is d3sp3 coz the inner d orbital participates..On the other hand if the ligand is weak (for e.g. F-) then the electrons of (n-1)d orbital of the metal does not pair up..this is sp3d2 coz outer d orbital will participate in bond formation with the ligands...
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