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Take the binary number and divide it into groups of 4 bits starting from the right hand side , if no group of 4 exists fill out leading 0's, then convert each group of 4 to a hex number directly e.g. 11111102 -> hex direct 111 1110 add leading zero 0111 1110 111 -> 7H 1110 -> 1410 ->EH 11111102 -> 7EH This is easily achieved in reverse by converting hex straight to binary i.e. divide the hex number into single hex digits from the right hand side and convert to binary each digit e.g. 7EH -> binary direct 7 -> 1112 E -> 1410 ->11102 7EH -> 11111102
Question : (a) The dynamic allocation problem is how to satisfy a request of size n from a list of free holes into memory. The best-fit, first-fit and worst-fit strategies are
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THE PROGRAM WILL CHOOSE TWO RANDOM NUMBERS,THEN PRINT THEM OUT AS AN ADDITION PROBLEM.THE PROGRAM WILL THEN ASK THE USERTO ENTER THE CORRECT ANSWER.IF THE ANSWER IS CORRECT,THE PRO
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