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Take the binary number and divide it into groups of 4 bits starting from the right hand side , if no group of 4 exists fill out leading 0's, then convert each group of 4 to a hex number directly e.g. 11111102 -> hex direct 111 1110 add leading zero 0111 1110 111 -> 7H 1110 -> 1410 ->EH 11111102 -> 7EH This is easily achieved in reverse by converting hex straight to binary i.e. divide the hex number into single hex digits from the right hand side and convert to binary each digit e.g. 7EH -> binary direct 7 -> 1112 E -> 1410 ->11102 7EH -> 11111102
Partitions and mounting A disk can be sliced into many partitions, or a partition can span multiple disks. Every partition can be either "raw", having no file system, or "cooke
What are Tree-structured directories We can generalize the directory structure to a tree of arbitrary height. This permits the user to create their own sub directories and to c
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Describe when you run an unlink() operation to remove a file on the ext3 file system. Be specific about what disk blocks have to be written where in what order. State your assumpti
In a table format, discuss the differences between the fixed partition and the variable partition memory organization in terms of the basic idea, memory structure, advantages
Q. Why High level languages need Compiler? High level languages - illustrations are COBOL, FORTRAN, PL/I andALGOL - are processed by interpreters andcompilers. A compilers is a
Q. Most WANs utilize only a partially connected topology. Why is this subsequently Answer: Cost. A completely connected network requires a link between every node in the netw
Problem: a) Define the term ‘process' and what are the different constituents of a process. b) In the three-state process model, what does each of the three states signify?
Minor page fault :I f the page is loaded in memory at the time the fault is started, but is not checked in the memory management unit as being loaded in memory, then it is named a
The following is a dump of a TCP header in hexadecimal format: 00CD0018 00000EF1 00000D5D 502200D1 01BF0010 We need to first split the above hex as such 00 CD 00 18 00 00
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