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Q. The given values are to be stored in a hash table
25, 42, 96, 101, 102, 162, 197
Explain how the values are hashed by using division technique of hashing with a table size of 7. Use chaining as the method of collision resolution.
Ans:
Table size=7
25%7=4
42%7=0
96%7=5
101%7=3
102%7=4
162%7=1
197%7=1
So collision resolution can be resolved as shown below:
for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a[k]=a[j]+i else if a[1]>4 && a[1] for 2 to a[1] a[j]= a{j]+5 else for 2to n a[j]=a[j]+i ..
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