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(x2y4m3)8
As a fundraiser a school is selling posters.The printer charges a $24 set up fee plus 0.20 for each poster. Then the cost y in dollars to print is given by the linear equation y=0.
w^2 + 30w + 81= (-9x^3 + 3x^2 - 15x)/(-3x) (14y = 8y^2 + y^3 + 12)/(6 + y) ac + xc + aw^2 + xw^2 10a^2- 27ab + 5b^2 For the last problem I have to incorporate the following words
A student''s tuition was $3008. A loan was obtained for 7/4 of the tuition. How much was the loan? The student''s loan was for?
The slope is -3 and the y-intercept is 4. How do I find a relation in the form y=mx+b which has a solution set line satisfying the given conditions?
The point in graph to the right are (1998),177),(20087),(2002,195 and (2004,207)where the y coordinates are the thousands complete part(a)and (b)(a use the first and last data poin
log(mn)
6[5b+9]=2b+9.
-200t^2+3600t-6400 if the goal was to raise 8500 what would be the price of each ticket?
2/3N + 4 = -26 solve for n, but what do i do with the fraction?
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