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Q: Can I overload operator == so it allow me compare two char[] by a string comparison?
A: No: at least one operand of particular overloaded operator should be of some user-defined type (most of the time it means a class).
However even if C++ let you to do this, which it doesn't, you wouldn't wished to do it anyway as you really should be using a std::string-like class instead of an array of char in the first place since arrays are evil.
A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of t
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