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Q Calculates function point value for a project with the following domain characteristics:
No. of I/P = 30
No. of O/P = 62
No. of user Inquiries = 24
No. of files = 8
No. of external interfaces = 2
Presume that all the complexity adjustment values are average. Presume that 14 algorithms have been counted.
Ans. We know
UFP=S Wij Zij where j=2 because all weighting factors are average.
=30*4+62*5+24*4+8*10+2*7
=120+310+96+80+14
=620
CAF=(0.65+0.01S Fi)
=0.65+0.01(14*3)
=0.65+0.42
=1.07
nFP=UFP*CAF
=620*1.07
=663.4»663
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