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Values from the iteration x = cos(x) are:
x0 = 0.8, x1 = 0.696707, x2 = 0.766959, x3 = 0.720024, x4 = 0.751790, x5 = 0.730468.
a) Calculate the sequence {yn} from Aitken's ?2 method. Given that the solution of x = cos x is 0.739085133 . . . , ?nd the rations between consecutive errors in {xn} (which approach a constant A) and also in {yn} (which approach another constant, say B). Con?rm that {yn} is converging twice as fast as {xn} (i.e. that B = A2).
b) Use Steffensen's method: from x0, x1, x2 calculate y0. Then start the iteration again from x3 = y0, and from x3, x4, x5 calculate y1.
procedure of tracing a closed loop
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Values from the iteration x = cos(x) are: x 0 = 0.8, x 1 = 0.696707, x 2 = 0.766959, x 3 = 0.720024, x 4 = 0.751790, x 5 = 0.730468. a) Calculate the sequence {y n } fr
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