An employee record has the following structure
struct employee {
int eno;
char name[22];
float salary;
char dept[10];};
(i) Calculate the record size R in bytes.
(ii) If the file has 500 records, calculate the blocking factor bfr and the number of blocks b, assuming an unspanned organization with block size B = 512 bytes.
(iii) Describe the unused space in each block and in the last block?

Ans: (i) 2 + 22+ 4 + 10 =38 bytes
(ii) bfr = floor( B/R) = [512/38] =13
Number of blocks b = ceiling (500/13) =39
(iii) Unused space in each block
= 512 - 38 *13 = 512 - 494= 18 bytes
Unused space in the last block
= ( 39 *13 - 500) * 38 bytes = (507 -500) * 38 bytes
= 7 * 38 =266 bytes