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The Maximum theoretical limit of channel is governed by Nyquist theorem, which says Bth = 2 x freq in hertz x log2L ( where L = number of level) Thus we have in this case Bth= 2x6000 = 12000 bits/sec = 12 KbpsFrom ans a we found that maximum channel capacity = 39949.2 bps Thus we have to achieve 50% i.e. = 20000 bps ( roughly)And we have from the earlier expression of ans b20000 = 2x 6000 x log2LOr log2L = 1.667
Now the number of levels have to be +ve integer. So L should be taken to the nearest integer that is 4 Thus we should have 4 discreet levels.
(NB cross check achieved bit rate with 4 levels = 2 x 6000x log2(4) = 2x6000x2 = 24000 bps i.e > 50%)
Forest and hill soils The hill and forest soils seem to be akin to soils developed in humid temperate regions, and have been found to include podsolised soils, brown Earths an
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