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By what percentage should the pressure of a given mass of gas be increased,so as to decrease its volume by 10% at a constant temperature.
This is a new generation of resistor having very low temperature coefficient of resistance. A metal foil made from a special alloy is bonded on to a flat ceramic substrate. The tem
what are the examples of like and unlike parallel forces?
Q. What are the various energy losses of a transformer? Energy losses in a transformer: (a) Hysteresis loss (b Copper loss (c) Eddy current loss (Iron loss) (d)
These resistors are usually of carbon composition, carbon film on a ceramic rod and sealed in evacuated glass tube. End connections are made up of copper clad nickel-iron alloy.
Forces on a Pendulum The weight, force because of tension, and total force exerted on the bob of a pendulum are displayed.
Friction is a microscopic constant and so macroscopic level area does not matter. But area would matter if the object we''re putting under study was microscopic, which isn''t in o
a sphere is at rest on a wall at a angle of 3,4(slpoe) to the left. it also rest against a vertical wall. we are to find the magnitude of the resultant force at the vertical wall.
Zehnder's balance This ingenious balance, which is very beneficial for demonstration experiments, can be constructed in a few minutes using pins, razor blade, cork and knitting
The magnitude of the force vector F is 270 newtons. They component of this vector is directed along the +y axis and has magnitude of 150 N. The x component is directed along the +x
mass=volume * density.By using this formula we can find the mass of sphere. Volume of sphere=(4/3)pi*r^3 V=(4/3)*3.14*(1*10^-2)^3=4.187*10^-6 Mass=(4.187*10^-6)*900=3768*10^-6kg
P1V1/T1=P2V2/T2 BUT TEMP. REMAINS CONSTANT. SO P1V1=P2V2 OR P1V1=P2(V1-V1/10) OR P1V1=P2*9V1/10 OR P1=9P2/10 OR P2=10P1/9 NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1 WHICH IS EQUAL TO 100/9%
P1V1/T1=P2V2/T2
BUT TEMP. REMAINS CONSTANT.
SO P1V1=P2V2
OR P1V1=P2(V1-V1/10)
OR P1V1=P2*9V1/10
OR P1=9P2/10
OR P2=10P1/9
NOW, PERCENTAGE INCREASE=(P2-P1)*100/P1
WHICH IS EQUAL TO 100/9%
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