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Calculate ionisation potential of the electron in the first exited state of singly ionised Helium atom is given by ionisation of Hydrogen atom to be 13.6 eV.
Ans: According to Bohr,
Ionisation potential of an element = (ionisation potential of hydrogen)/ n2
We know for helium n=2
Hence IP of He = 13.6/ 22= 3.4 eV
Rutherford's scattering experiment is related to the size of the: (1) Nucleus (2) Atom (3) Electron (4) Neutron Ans: Nucleus
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