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Program is to take two arguments and returns the string:
Program is to take two arguments and returns the string which is larger the larger string has larger ascii value invoke function from main
int compare(char *st,char *st2);
void main()
{
clrscr();
int x;
char st[20],st2[20];
int ans;
cout<<" enter the first string ";
gets(st);
cout<<" enter the second string ";
gets(st2);
ans=compare(st,st2);
if (ans==0)
cout<<" the larger string is "< else cout<<" the larger string is "< } int compare(char *st,char *st2) { int i=0; while(st[i]!='\0' && st2[i] != '\0') { if (st[i]==st2[i]) { i++; } else if (st[i]>st2[i]) return 1; else return 0; } return 0; }
else
cout<<" the larger string is "< } int compare(char *st,char *st2) { int i=0; while(st[i]!='\0' && st2[i] != '\0') { if (st[i]==st2[i]) { i++; } else if (st[i]>st2[i]) return 1; else return 0; } return 0; }
}
int compare(char *st,char *st2)
int i=0;
while(st[i]!='\0' && st2[i] != '\0')
if (st[i]==st2[i])
i++;
else if (st[i]>st2[i])
return 1;
return 0;
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#questio#A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string
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