C Program to FIND THE EVEN WORDS IN THE STRING

#include conio.h>

#include stdio.h>

void main()

{

          char a[50],temp;

          int i=0,k=0,l[25],c=0,r=0;

          clrscr();

          for(i=0;i<25;i++)

          {

                   l[i]=0;

          }

          i=0;

          printf("ENTER THE STRING: ");

          do

          {

                   a[i++]=getchar();

          }while(a[i-1]!='\n');

          a[i]='\0';

          printf("%s",a);

          for(i=0;a[i]!='\0';i++)

          {

                   if(a[i]==' ' || a[i]=='\n')

                   {

                             temp=a[k];

                             a[k]=a[i-1];

                             a[i-1]=temp;

k=i+1;

                             c++;

                   }

                   else

                   {

                             l[c]++;

                   }

          }

          for(i=0;l[i]!=0;i++)

          {

                   if(l[i]%2==0)

                   {

                    r++;

                   }

          }

          printf("%s\n",a);

          printf("THE TOTAL NO OF EVEN WORDS ARE:  %d",r);

          getch();

}

OUTPUT :

ENTER THE STRING: KAMLESH D MENGAR

HSELMAK D RAGNEM

THE EVEN WORDS ARE : 1