C program for the no are in ascending order , C/C++ Programming

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#include stdio.h>

#include conio.h>

#include string.h>

void main()

{

          int i=0,j=0,k=0,l=0;

          int a[3][3],temp[3][3];

          clrscr();

          for(i=0;i<3;i++)

          {

                   for(j=0;j<3;j++)

                   {

                             a[i][j]=0;

                             temp[i][j]=0;

                   }

          } i=0;j=0;

          for(i=0;i<3;i++)

          {

                   for(j=0;j<3;j++)

                   {

                             printf("ENTER THE VALUE %d %d: ",i+1,j+1);

                             scanf("%d",&a[i][j]);

                   }

          }

          for(i=0;i<3;i++)

          {

                   for(j=0;j<3;j++)

                   {

                             for(k=0;k<3;k++)

                             {

                                      for(l=0;l<3;l++)

                                      {

                                                if(a[i][j]

                                                {

                                                          temp[i][j]=a[i][j];

                                                          a[i][j]=a[k][l];

                                                          a[k][l]=temp[i][j];

                                                }

                                      }

                             }

                   }

          }

          printf("\nNO ARE IN ACCENDING ORDER");

          printf("\n");

          for(i=0;i<3;i++)

          {

                   for(j=0;j<3;j++)

                             printf("%d\t",a[i][j]);

                   printf("\n");

          }

          getch();

}

 

OUTPUT :

ENTER THE LIMIT OF ELEMENTS: 3

ENTER THE NO 1 : 2  ENTER THE NO 2 : 3

ENTER THE NO 3 : 4

THE EVEN NO.S ARE 2  THE ODD NO.S ARE 1

THE TOTAL OF EVEN NO IS 6

THE TOTAL OF ODD NO IS 3

THE AVG. OF ALL EVEN NO IS 3.0000

THE AVG. OF ALL ODD NO IS 3.0000

 


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