C Program for FIND EVEN & ODD NO.S IN THE ARRAY

#include stdio.h>

#include string.h>

#include conio.h>

void main()

{

          int i=0,j=0, l_e[100],l_o[100];

          int a[100],odd=0,even=0,sum_even=0,sum_odd=0;

          float avg_e=0,avg_o=0;

          for(i=0;i<100;i++)

          {

                   a[i]=0;

                   l_e[i]=0;

                   l_o[i]=0;

          }

          i=0;    clrscr();

          printf("\nENTER THE LIMIT OF ELEMENTS: ");

          scanf("%d",&j);

          for(i=0;i

          {

                   printf("\nENTER THE NO %d: ",i+1);

                   scanf("%d",&a[i]);

                    if(a[i]%2==0)

                   {

                             sum_even=sum_even+a[i];

                             even++;

                             avg_e=sum_even/even;

                             l_e[i]=a[i];

                   }

                   else

                   {

                             sum_odd=sum_odd+a[i];

                             odd++;

                             avg_o=sum_odd/odd;

                             l_o[i]=a[i];

                   }

          } i=0;

          printf("\nTHE EVEN NO.S ARE %d",even);

          printf("\nTHE ODD NO.S ARE %d",odd);

          printf("\nTHE TOTAL OF EVEN NO.S ARE %d",sum_even);

          printf("\nTHE TOTAL OF ODD NO.S ARE  %d",sum_odd);

          printf("\nTHE AVERAGE OF ALL EVEN NO.S IS %f",avg_e);

          printf("\nTHE AVERAGE OF ALL ODD NO.S IS  %f",avg_o);

          getch();

}

OUTPUT :

ENTER THE NO 1 1 : 2

ENTER THE NO 1 2 : 6

ENTER THE NO 1 3 : 3

ENTER THE NO 2 1 : 4

ENTER THE NO 2 2 : 7

ENTER THE NO 2 3 : 8

ENTER THE NO 3 1 : 9

ENTER THE NO 3 2 : 1

ENTER THE NO 3 3 : 2

NO ARE IN ASCENDING ORDER

1          2          2

3          4          6

7          8          9