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Q. Briefly explain about Wheatstone Bridge?
Null measurements are made with bridge circuits and related configurations. They differ from direct measurements in that the quantity being measured is compared with a known reference quantity. The balancing strategy avoids undesirable interaction effects and generally results in more accurate measurement than the direct one.
By far the most common is the Wheatstone bridge designed for precise measurement of resistance. Figure 1.4.2 shows the basic circuit inwhich themeasurement of an unknown resistance Rx is performed by balancing the variable resistances Ra and Rb until no current flows through meter A. Under this null condition,
where Rs is the known standard resistance. There are other bridge-circuit configurations to measure inductance and capacitance. Typical instruments utilizing bridge circuits are found in strain gauges measuring stress and in temperature measuring systems with thermocouples and thermistors.
Q. What is the speciality of a darlington transistor? A darlington pair behaves like a single transistor with a very high current gain. The total gain of the darlington is the
A 3 phase, 6 pole induction motor is rated at 400hz, 150v, 10h.p., 3% slip at rated power output. The windage and friction loss is 200w at rated speed. With the motor operating at
Prepaid Metering Prepaid metering is the state of art for single and three-phase although current metering, and should be implemented through utilities desirous of protecting
Q. What is an oscillator? Discuss the advantages of Oscillators ? An oscillator is a system consisting of active and passive circuit elements to produce a sinusoidal or other r
a shunt motor supplied at 230V rms runs at 900rev/min when the armature current is 30A.the resistance of the armature circuit is 0.4 ohms.find the armature input
ABCD propagation of an optical ray through a system can be explained by a simple 2_2 matrix. In ray optics, the characteristic of a system is given by the corresponding ray matrix
Q. Consider the bridge circuit given in Figure with R 1 = 24 k, R 2 = 48 k, and R 3 = 10 k. Find R when the bridge is balanced with V = 0.
Q. Give the principle of biasing a FET amplifier. To correctly bias the FET, the gate needs to be negative with respect to the source. Bias is obtained in the following manner:
Each of the following functions is abs(H(jw))^2 of a certain network function H(s). Obtain all the possible H(s) for each given abs(H(jw))^2. [(w^4)+25]/[(w^4)+(12w^2)+49]
how can I simulate air variable capacitors in cst simulator?
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