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A non uniform rod AB has a mass M and length 2L the mas per unit length of the rod is mx at a point of the rod distant x from A.find the moment of inertia of this rod about an axis perpendicular to the rod (!)through A (2)through the mid point of ABAns) consider a strip of the rod ''dx'' at a length ''x'' from A.mass of the small strip is mx*dx.moment of inertia of the small strip about A IS m*x*dx*x*x.on integrating we get moment of inetia about A as 4*m*L*L*L*L.ABOUT MID POINT OF AB.consider a strip of length ''dx'' at a distance of x from mid point P.mass of it is m*(L-x)*dx.moment of inertia of half of the rod about P is m*(L-x)*dx*x*x.on integration we get moment of inertia of half of the rod.similarly do for the other half.adding them we get the answer.
#question.i want to know the number of pixels related to the actual phase value in an image and want to separate the zero phase valued pixels from the image.
In accrued model of a rotating diatomic molecule of (Cl 2 ), the two Cl atoms are 2.00´ 10? -10 m apart and rotate about their center of mass with angular speed w = 2.00 ´10 12 ra
how to derive the formullar n=[(sin(A+D)/2)/(SIN (A/2))
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