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ASSUME: Assume Logical Segment Name:-
The ASSUME directive which is used to inform the assembler, the specified names of the logical segments to be consider for different segments which is used in the program. In the assembly language program, each of thesegment is given a particular name. For instance, the code segment can be given the name CODE; data segment can be allotted the name DATA etc. The statement ASSUME CS: CODE directs the assembler that the machine codes are available in a segment named CODE, and so the CS register is to be loaded having the address (segment) allotted by operating system for the label CODE, while loading. IN the same manner, ASSUME DS : DATA denote to the assembler that the data items related to the program, are available in a logical segment named DATA, and the DS register can be initialised by the segment address value decided by the operating system for the data segment, whereas loading. It then assumed the segment DATA as a default data segment for each memory operation, that is related to the data and the segment CODE as a source segment for the machine codes of the program. The ASSUME statement is necessary at the starting of each assembly language program, without which a message 'CODE/DATA EMITTED WITHOUT SEGMENT' may be issued by an assembler.
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Instruction set of 8086 : The 8086/8088 instructions are categorized into the following major types. This section describes the function of each of the instructions with approp
This is a short program to practice assembly language loops and if/else statements. You will use various jump commands and the cmp instruction. The program will generate a random
) What is the difference between re-locatable program and re-locatable data?
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The main objective of the assignment is to explore the knowledge regarding parallel ports of a computer system. You can read and write datato/from the parallel port using IN and OU
this is my first project i dont know where to start
Architecture Of 8088 The register set of 8088 is accurately the same as in to 8086. The architecture of 8088 is also same to 8086 except for 2 changes; a) 8088 has 4-byte instr
ADC: Add with Carry:- This instruction performs the similar operation a like ADD instruction, but adds the carry flag bit (which might be set as a result of the previous calculatio
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