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Are the side emitting fibers with reflecting core more luminous?
To answer this honestly is very much as trying to find out the sex of the angels. When a side emitting light guide has a center reflecting core this would appear that this would issue more light omni directionally, it is to say as: if the light guide was suspended into mid-air and viewed with any angle. The problem with which argument is that that optics are, normally connected to a support and viewed from fixed angles. There opaque centrepiece, in this case, would impede the passage of light from behind this core and therefore the optic would have less light obtainable to the viewers. Side-emitting light guides are sheathed into a transparent cover and the viewer, through transparency, has the benefit of the light escaping not only by the individual fibers placed directly opposite his line of vision but also by the ones behind.
If we acquire a glass tube filled with a colored liquid and light this up by one end, we could view the complete of the mass as a lit-up cylinder. If we, after that place a concentric opaque core, from a specified direction we would have less vision of the cylinder mass. Similar would hold true with any transparent cylinder. To prove such argument is a practical impossibility since this would require two optics with and without core of similar size and optical properties, placed accurately, on the similar spot in an illuminator. In my outlook, no matter the patents, the termed as center reflecting cores do not add more light to a guide and probably rests light to the viewer and the system as a complete.
Megavoltage therapy: Kerst developed the betatron which accelerates electrons to high energy .It open a new radiation therapy era-the supervoltage or megavoltage era.Another
If the electrons striking the target eject an electron from the K-shell of the atom, a vacancy is crated in the K-shell. Instantly an electron from one of the outer most shell, say
Q. Find the electric potential at a distance 0.09 m from a charge of 4 X 10 -7 C. The electric potential V = ( 1/4πεo ) q /r = ( 9 X 10 9 X 4 X 10 -7 )/ 9 X 10 -2 = 4 X 10
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