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ADD: Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destination) or memory location. The outcome is in the destination operand. However, the source and destination both operands can't be memory operands. That means memory and memory addition is impossible. Also the contents of segment registers can't be added by using this instruction. All of the condition code flags are affected, depending on the result. The instance of this instruction is given along with the equivalent modes.
Example :
1. ADD AX, 0100H Immediate
2. ADD AX, BX Register
3. ADD AX, [SI] Register indirect
4. ADD AX, [5000H] Immediate
5. ADD [5000H] 0100H Immediate
6. ADD 0100H Destination AX (implicit)
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
A good starting point for your program is the toupper.asm program shown in class. It already queries the user for input and sets up a loop that looks at each character of the input
SHL/SAL : Shift logical/Arithmetic Left: These instructions shift the operand byte or word bit by bit to the left and insert 0 in the newly introduced least significant bits. In c
Hand shaking : Handshaking, or 2-way handshaking, is 1 type of strobe operation. It typically involves 2 handshaking lines: an output line to denote when the board is ready an
Register Organization of 8086 8086 has a great set of registers containing special purpose and general purpose registers. All the 8086 resisters are 16-bit registers.
Entering a Program In this section, we will explain the procedure for entering a small program on IBM PC with DOS operating system. Assume a program of addition of 2 bytes, as
You have to write a subroutine (assembly language code using NASM) for the following equation.
Program : Write a program to perform a one byte BCD addition. Solution : It is consider that the operands are in BCD form, but the CPU considers it as hexadecimal and acco
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You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
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