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ADD: Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destination) or memory location. The outcome is in the destination operand. However, the source and destination both operands can't be memory operands. That means memory and memory addition is impossible. Also the contents of segment registers can't be added by using this instruction. All of the condition code flags are affected, depending on the result. The instance of this instruction is given along with the equivalent modes.
Example :
1. ADD AX, 0100H Immediate
2. ADD AX, BX Register
3. ADD AX, [SI] Register indirect
4. ADD AX, [5000H] Immediate
5. ADD [5000H] 0100H Immediate
6. ADD 0100H Destination AX (implicit)
Prime Finder - assembly program: Problem: Prime Finder In this problem you will write a small program that tests whether a given integer is a prime number or not. Let's
External Hardware-Interrupts External hardware-interrupts are generated by controllers of external devices or coprocessors and are connected to the processor pin for Non Mask a
Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************
give the explaination of timing diagram minimum mode memory write cycle
$NOMOD51 $NOSYMBOLS ;***************************************************************************** ; Spring 2013 Project ; ; FILE NAME : Project.ASM ; DATE : 3/30/20
Data copy/transfer Instructions MOV: This data transfer instruction transfers data from one register or memory location to another register or memory location. The source can
CALL : Unconditional Call:- This instruction is utilized to call a subroutine from a basic program. In case of assembly language programming, the term procedure is utilized int
Register Organization of 8086 8086 has a great set of registers containing special purpose and general purpose registers. All the 8086 resisters are 16-bit registers.
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
I need help with assembly programing
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