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In the last two sections of this chapter we desire to discuss solving equations & inequalities that have absolute values. We will look at equations along with absolute value in them in this section.
However, before solving first we must have a brief discussion of just what absolute value is.
The notation for the absolute value of p is |p|. Note as well that the absolute value bars are not parentheses and in several cases don't act as parentheses so be careful with them.
There are two ways to describe absolute value. There is geometric definition & a mathematical definition. We will look at both.
1/1+x+1/y+1/1+z+1/x+1/1+y+1/z=1
9-6x>3-5x
adding fractions
I have 4.80 I need to separste into nichols, dimes and pennies. The first digit has to equal The first digist is l1 less the the first and the 2nd is once less than the third and
We now can also combine the two shifts we only got done looking at into single problem. If we know the graph of f ( x ) the graph of g ( x ) = f ( x + c ) + k will be the graph of
The last set of transformations which we're going to be looking at in this section isn't shifts, but in spite of they are called reflections & there are two of them. Reflection
what is 8 14/10 in simplest form
if A is an ideal and phi is onto S,then phi(A)is an ideal.
It is probably the easiest function which we'll ever graph and still it is one of the functions which tend to cause problems for students. The most general form for the constant
X6-81X2=0 what is the real solution
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