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We've dealt along with this function many times already. Now it's time to graph it. First, let's remember ourselves of the definition of the absolute value function.
It is a piecewise function & we've illustrated how to graph these already. All that we have to do is obtain some points in both ranges & plot them.
Here are some function evaluations.
x
f(x)
0
1
-1
2
-2
Following is graph of this function.
Hence, it is a "V" shaped graph.
how do you work out 2x-y=32 2x+y=60
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81x^5-49x^3=0
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need help on intro into algebra college homework
(9x10^1)(2.3x10^0)
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show that -b/b-a may be properly changed to b/a-b...show steps
For these properties we will suppose that x > 0 and y > 0 log b ( xy ) = log b x + log b y log b ( x/y) = log b x - log b y log b (x r ) = r log x If log
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