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We've dealt along with this function many times already. Now it's time to graph it. First, let's remember ourselves of the definition of the absolute value function.
It is a piecewise function & we've illustrated how to graph these already. All that we have to do is obtain some points in both ranges & plot them.
Here are some function evaluations.
x
f(x)
0
1
-1
2
-2
Following is graph of this function.
Hence, it is a "V" shaped graph.
2x+5=-8
you can use the equation -b +or- Square root of bsquared - 4(a)(c)over 2a. But if you number for b is b is negative it will become positive??? And if the number was + it will Beco
Simpler method Let's begin by looking at the simpler method. This method will employ the following fact about exponential functions. If b x = b y then x
17b-29=39
how do i find the y-intercept when i already found the slope?
How do you solve the problems?
4=x+5 3x+4=-11
2x+y/x+3y=-1/7and 7x+36y=47/3 hence find p if xy=p=x/y
Sketch the graph parabolas. f (x ) = 2 ( x + 3) 2 - 8 Solution In all of these we will just go through the procedure given above to determine the required points and t
Solve following equations. (a) x 2 -100 = 0 (b) 25 y 2 - 3 = 0 Solution There actually isn't all that much to these problems. To use the square root property a
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