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We've dealt along with this function many times already. Now it's time to graph it. First, let's remember ourselves of the definition of the absolute value function.
It is a piecewise function & we've illustrated how to graph these already. All that we have to do is obtain some points in both ranges & plot them.
Here are some function evaluations.
x
f(x)
0
1
-1
2
-2
Following is graph of this function.
Hence, it is a "V" shaped graph.
Actually these problems are variants of the Distance/Rate problems which we just got done working. The standard equation which will be required for these problems is, As y
y=2/3x-1
10x^7y^3 and 25xv^8y^4
#question.P(x) = –x2 + 110x – 1,000. P(5), P(50), P(120) plot on graph
We now can also combine the two shifts we only got done looking at into single problem. If we know the graph of f ( x ) the graph of g ( x ) = f ( x + c ) + k will be the graph of
x/4a^3 / 5x^3/6a^5x
x cubed plus 27??
In the earlier two sections we've talked quite a bit regarding solving quadratic equations. A logical question to ask at this point is which method has to we employ to solve a giv
Utilizes augmented matrices to solve out each of the following systems. x - y = 6 -2x + 2 y = 1 Solution Now, already we've worked this one out therefore we know that
Perpendicular to y=3x-2 and through the point (6,4)
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