radioactive substance, Physics

Assignment Help:

A certain radioactive substance has a half-life of 40 minutes. How much of an original 100 grams substance will remain after 2 hours?

solution) m= m0/2t/T

m=100 gms..

t=2 hours=2*60=120 min..

T=40 min

m=100/2120/40

m=100/23

m=100/8

m=12.5 gms.


Related Discussions:- radioactive substance

What is the unit of capacitance in si system of measure, In the SI system o...

In the SI system of measure, what is the unit of capacitance? Ans: In the SI system of measure, farad is the unit of capacitance.

What is the use of control rods, Q. What is the use of control rods? Mentio...

Q. What is the use of control rods? Mention any two control rods. The control rods are utilized to control the chain reaction. They are extremely good absorbers of neutrons. Th

OPTICS, How do I make a terrestrial telescope?

How do I make a terrestrial telescope?

Determine the weight of a body, Determine the weight of a body. Princip...

Determine the weight of a body. Principle: When a spring is fixed at one end and a force is applied to the other end the stretching of the spring is proportional to the applie

Define the cylinders with massive piston, Define the Cylinders with Massive...

Define the Cylinders with Massive Piston? Assay moles of an ideal monatomic gas placed in a vertical cylinder. The top of the cylinder is blocked by a piston of mass M and cro

Newton''s 2nd Law of Motion, A rocket weighs 9800N. What applied force give...

A rocket weighs 9800N. What applied force gives it a vertical acceleration of 4m/sec/sec?

Determine the minimum pressure, The water level in a tank is 20 m above the...

The water level in a tank is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end of the hose is pointed straight up. The tank is at sea

Galvanometer., why horse shoe magnet is use in galvanometer

why horse shoe magnet is use in galvanometer

3/11/2013 3:37:25 AM

half life = 40minutes =2/3 hours

t(1/2)=(ln2 /k)

then k=(ln2/t(1/2)) = ln2/(2/3) = 3/2*(ln2)

origianl substance y0= 1000 grams

y=y0e-kt

y= 1000*(e-(3/2(ln2))*2 ) = 1000/8 = 125 grams

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd