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Prove that the area of a rhombus on the hypotenuse of a right-angled triangle, with one of the angles as 60o, is equal to the sum of the areas of rhombuses with one of their angles as 60o drawn on the other two sides.
Ans: Hint: Area of Rhombus of side a & one angle of 60o
= √3/2 x a x a = √3/2 a2
10+2=
A circle touches the side BC of a triangle ABC at P and touches AB and AC when produced at Q and R. Show that AQ= 1/2 (perimeter of triangle ABC) Ans: Since the length o
Two angles are complementary. The calculate of one angle is four times the measure of the other. Evaluate the measure of the larger angle. a. 36° b. 72° c. 144° d. 18°
#The digits 1,2,3,4and 5 are arranged in random order,to form a five-digit number. Find the probability that the number is a. an odd number. b.less than 23,000
Find no. of non negative integral solutions x 1 +x 2 +x 3 +4x 4 =20 Solution) 140. Break them into prime factors . Put 4 = 2^2 and every variable will have factors in 2,3,5 with
how to solve this? y = 7x - 12 y = x2 Solve the system using substitution.
Relationship between the inverse sine function and the sine function We have the given relationship among the inverse sine function and the sine function.
An ice-cream cone has a hemispherical top. If the height of the cone is 9 cm and base radius is 2.5 cm, find the volume of ice cream cone.
where will we use least cost method
In order to compute the inequalities of the form where n 1 , n 2 , ....... , n k , m 1 , m 2 , ....... , m p are natural and real numbers and a 1 , a 2 , ... , a k ,
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