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Prove that the area of a rhombus on the hypotenuse of a right-angled triangle, with one of the angles as 60o, is equal to the sum of the areas of rhombuses with one of their angles as 60o drawn on the other two sides.
Ans: Hint: Area of Rhombus of side a & one angle of 60o
= √3/2 x a x a = √3/2 a2
Find the value of x if 2x + 1, x 2 + x +1, 3 x 2 - 3 x +3 are consecutive terms of an AP. Ans: a 2 -a 1 = a 3 -a 2 ⇒ x 2 + x + 1-2 x - 1 = 3x 2 - 3x + 3- x
what is the nearest ten thousand of 92,892?
Taking 2^x=m and solving the quadratic for getting D>=0 we get range= [3/4 , infinity )
i have trouble going through problem in this lesson. Markdown and Markups are theh ones im stuck in
Application of rate change Brief set of examples concentrating on the rate of change application of derivatives is given in this section. Example Find out all the point
(a+b+c)2=
Marty used the subsequent mathematical statement to show he could change an expression and still get the similar answer on both sides: 10 × (6 × 5) = (10 × 6) × 5 Which mathematica
DISTINCT EIGENVALUES -SYSTEM SOLVING : E xample Solve the following IVP. Solution : Therefore, the first thing that we must to do that is, get the eigenvalues
The sum of the smallest and largest multiples of 8 up to 60 is?
How many types of ogives?
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