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Treatment of Na2PdCI4 with 3-chloro-2-methyl-1-propene under an atmosphere of CO yields the dimer [(113- C4H7 )PdClb (A). The 1H NMR spectrum of A at 298 K shows 3 signals: a singlet at 0 2.2 and 2 doublets at 2.9 and 3.8 ppm with the relative intensities of the signals being 3:2:2 respectively. Addition of 2 moles of AsPh3 to the dimer A gives complex B (molar ratio As:Pd:CI = 1:1:1). 1H NMR spectrum of B at 195 K displays a singlet at 0 2.1 and 4 doublets at 0 2.7, 3.2, 3.6 and 4.5 with relative intensities 3:1:1:1:1 as well as aromatic protons due to AsPh3. On warming a solution of B the 1H NMR changes to show two singlets at 2.1 and 3.5 with relative intensities 3:4 in addition to resonances due to the aromatic protons.
(a) Give the structures of A and B and describe the bonding between the organic group and the palladium in A.
(b) Interpret and explain the NMR spectrum of A
(c) Interpret and explain the NMR spectrum of B at 195K
(d) Discuss what happens when B is warmed to 323K and how it accounts for the change in the NMR spectrum.
(e) How would you make the organic group in B more susceptible to nucleophilic attack.
if we impose any rule and regulation on clasical model like not expoit polutionso what is effect on factor of clasical model
Treatment of Na2PdCI4 with 3-chloro-2-methyl-1-propene under an atmosphere of CO yields the dimer [(11 3 - C 4 H 7 )PdClb (A). The 1H NMR spectrum of A at 298 K shows 3 signals: a
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