Q1. While on vacation you rent a moped and go cruising around a tropical island. If you take a 10.0 degree banked curve with a radius of 15.0 meters at 12.0 m/s, what is the minimum coefficient of static friction between your tires and the road to keep the tires from slipping as you negotiate the curve?

Q2. A 10.0 g bullet is fired horizontally into a 104g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 157N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 70.0cm, what was the speed of the bullet at impact with block?

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What was the speed of the bullet at impact with block : While on vacation you rent a moped and go cruising around a tropical island. If you take a 10.0 degree banked curve with a radius of 15.0 meters at 12.0 m/s, what is the minimum coefficient of static friction between your tires and the road to keep t.. |

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What is the magnitude of the average acceleration : A particular organ pipe can resonate at 213 Hz, 355 Hz, and 497 Hz, but not at any other frequencies in between. What is the fundamental frequency of pipe. |

## By how much has child reduced her mouth pressureA beam of parallel rays from a 24 MHz citizens band radio transmitter passes between two electrically conducting (hence opaque to radio waves) buildings located 45.00 m apart. What is an angular width of the beam as it emerges from between the buildi.. |

## What is the magnification of imageA 180g block hangs from a spring with spring constant 6.0 N/m. At the block is 31cm below the equilibrium point and moving upward with a speed of 98.0cm/s. What is the block's position at t = 9s. |

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## Find out the weight of the automobileThe four tires of an automobile are inflated to a gauge pressure of 2.10E+5 Pa. Each tire has an area of 0.0267 m2 in contact with the ground. Find out the weight of the automobile. |

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## What force is applied to the driver by his seat beltNote the gravitational acceleration of equatorial sea level is g = 32.0088ft/s^2 and that its variation is 0.003ft/s^2/ 1000ft ascent. find the height in miles above its point for which g = 30.504 ft/s^2 and what is the weight of a 180lb man on top o.. |

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