### What is the speed of the block after the collision

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##### Reference no: EM13322515

A 0.45 caliber bullet (m = 10.7 g) is fired into a large block of wood (M = 0.750 kg) so that the bullet becomes lodged in the block. Earlier ballistics tests showed that the speed of the bullet before the collision is 320 m/s. After the collision, the block is observed to slide across the floor (u_k = 0.350) for a distance (D) before coming to a stop. Anser the following:

(a) What was the momentum, in kgm/s, of the bullet before the collision?

(b) What is the speed of the block after the collision?

(c) How much energy is lost due to friction as the block slides across the floor?

(d) How far (D) will the block slide before stopping?

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