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Q. An emf of 24.0 V is applied to a coil with an inductance of 58.0 mH and a resistance of 0.41 Ω.
a) Determine the energy stored in the magnetic field when the current reaches one fourth of its maximum value.
b) How long does it take for the current to reach this value?
Answer: a)The maximum current, after a long time has elapsed, will be 24/0.41 = 58.5A. A quarter of this is 14.63A. Energy stored in an inductor is 0.5*L*I^2 = 6.21J
b) you can use I(t)/ Imax =1 - exp(-t*R/L) where I(t) is the current at time t (14.63A), Imax is the maximum current (58.5A), R is the resistance, L the inductance
0.75 = exp(-t*7.07)
t*7.07= 0.288
t = 40.7ms
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