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Te ccl4 formed in the first step is used as a reactant in

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Reference no: EM13593259

Each step in the process has a 60 % yield. CH4 +4 Cl2 ----> CCl + 4HCl CCl4 + 2HF ---> CCl2F2 + 2HCl

The CCl4 formed in the first step is used as a reactant in the second step. If 2.50 mol of CH4 reacts, what is the total amount of HCl produced? Assume that Cl2 and HF are present in excess.

Reference no: EM13593259

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