Each step in the process has a 60 % yield. CH_{4} +4 Cl_{2} ----> CCl + 4HCl CCl_{4} + 2HF ---> CCl_{2}F_{2} + 2HCl

The CCl_{4} formed in the first step is used as a reactant in the second step. If 2.50 mol of CH4 reacts, what is the total amount of HCl produced? Assume that Cl_{2} and HF are present in excess.

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Te ccl4 formed in the first step is used as a reactant in : each step in the process has a 60 yield. ch4 4 cl2 ----gt ccl 4hcl ccl4 2hf ---gt ccl2f2 2hclthe ccl4 formed in the |

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