Starting with the child closest to the center

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A very large seesaw has room for four children to sit on either side. The first child may sit 1 m from the center, the second may sit 2 m from the center, the third child sits 3 m from the center and the fourth child 4 m. The parent of the children, whose mass is 60 kg, sits 4 m away from the center on the right hand side. Their four children (A = 15 kg, B=25 kg, C=30 kg, D=40 kg) want to sit on the other side so that the seesaw is balanced in a horizontal position. In what order should they sit starting with the child closest to the center. (The answer should be in a form like ABCD or DCBA etc.) You must show your work!

Reference no: EM132521080

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