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or the hairline gene, the man's genotype is Ww and the woman's is ww.For the color vision gene, the man's genotype is X N Y and the woman's is X n X n.Here are some probabilites:What is the chance that any son that the couple has will be color blind with a widow's peak? 1/2If the couple has a child, what is the chance that it will be a daughter with a widow's peak? 1/4Suppose the couple had a daughter with a normal color vision and a widow's peak. What is the chance that she is homozygous for both genes? 0What is the chance that any daughter the couple has will be color blind with a straight hairline? 0
Can someone explain how these probabilities were determined? I know how to calculate probability with the multipilcation and addition rule, Punnett square, etc. I am being thrown off by the son and daughter concept. What is the best way to determine the probability without using a Punnett square?
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At another locus, sepia eyes are inherited as an autosomal (non sex linked) recessive. The presence of the white eye phenotype (x superscript w x superscript w in females, x superscript y in males) masks sepia phenotype, so regardless of the sepia ge..
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