Show that penny lands a distance from base of coffee table

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Reference no: EM13979372

Given: A penny moving at speed "v" slides off the horizontal surface of a coffee table a vertical distance "y" from the floor.

Question: Show that the penny lands a distance v√2y/g from the base of the coffee table.

Problems: Need detailed answer of how you move to this final formula, In my physics book there I have Located formulas: d = ½ gt² and t = √2d/g. I'm just not sure how to get to the final formula.

Reference no: EM13979372

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Show that penny lands a distance from base of coffee table : Given: A penny moving at speed "v" slides off the horizontal surface of a coffee table a vertical distance "y" from the floor. Show that the penny lands a distance v√2y/g from the base of the coffee table.

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