Solution-Opposite direction of the work

Opposite direction of the work

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Reference no: EM131345663

A block of mass m = 5.0 kg is pulled along a rough horizontal surface by a rope as sketched in the figure below. ( rope is at a 30 degree angle from the horizontal) The tension in the rope is 50 N, and the coefficient of kinetic friction between the block and the surface is μK = 0.35. (a) If the block travels a distance of 6.0 m along the surface, what is the work done by the rope? 259.8J (b) Find the work done by friction on the block. I tried to use Workk= coefficient of friction x mass x g x displacement = .35(5kg) (9.8) (6m)= 102.9 and then negative because it is in the opposite direction of the work done by the rope. but this is not correct. Then I tried the same formula and added cos(angle) Workk= - (coefficient of friction) (mass) (g) (displacement) (cos(angle)) =(.35) (5) (9.8) (6) (cos 150) = -89.1

Reference no: EM131345663

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Opposite direction of the work : I tried to use Workk= coefficient of friction x mass x g x displacement = .35(5kg) (9.8) (6m)= 102.9 and then negative because it is in the opposite direction of the work done by the rope. but this is not correct. Then I tried the same formula a..

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Opposite direction of the work

Reference no: EM131345663

Reference no: EM131345663

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