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ELECTRO CHEMICAL PROBLEM NO3-
QUESTION -3
A deposit of 0.5 kg of silver per hour is obtained on the cathode of silver voltameter of resistance 0.7 milli -ohm . how much potential difference must be maintained between the plates ? given atomic mass of silver =108 g 1 FARADAY = 96500 C/ mole
Answer - silver is mono valent , therefore equivalent weight of silver = atomic weight = 108 g E.C.E of silver , = Z = Equivalent weight /F = 108 /96500 = 0.001119 g/CT = t =60 *60 =3600 secs , m= 0.5 = 0.5*1000 =500 g Now , current , =I = m /z.t = 500 /0.001119 *3600 = 124.12 amps Potential difference = P.D = I.R = 124.12 *0.7 /1000 = 0.087 VOLTS
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