Find the original temperature of the ice

Reference no: EM13514998

I take 1.0 kg of ice and dump it into 1.0 kg of water and, when equilibrium is reached, I have 2.0 kg of ice at 0°C. The water was originally at 0°C. The specific heat of water = 1.00 kcal/kg×°C, the specific heat of ice = 0.50 kcal/kg×°C, and the latent heat of fusion of water is 80 kcal/kg. The original temperature of the ice was:

Reference no: EM13514998

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