Find the chi-square critical value for goodness

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1. Find the Chi-Square critical value for goodness of fit where alpha is the level of significance and k is the number of possible outcomes for each trial.

alpha (level of significance) =0.01 and k = 9, where degree of freedom = k - 1

13.362

17.535

20.090

21.955

2. In a χ2 test of independence between gender and kinds of phobias, the null hypothesis was rejected. The proper conclusion is that

gender and phobias are independent of each other

gender and phobias are related to each other

none of the choices are correct

knowing a person's phobia gives you no clue to his or her gender

3. The sum of the expected frequencies must be equal to

(R - 1)(C - 1)

none of the choices are correct

the sum of the observed frequencies

the df

4. Find the Chi-Square critical value for the test of association where alpha is the level of significance, R is the number of rows and C is number of columns.

alpha (level of significance) =0.10 and R = 2, C = 3, where degree of freedom = (R - 1)(C - 1)

6.51

2.56

5.13

3.45

5. In a χ2 test of independence between age and personality type, the null hypothesis was rejected. The proper conclusion is

age and personality are related to each other

age and personality are independent of each other

this was the wrong test

age and personality are measured on different scales and cannot be related with statistics

6. Suppose you obtained a Spearman rs of .38 from 26 pairs of scores. For a two-tailed test, such a correlation coefficient should be considered

significant at the .05 level

significant at the .001 level

significant at the .01 level

not statistically significant

7. Suppose a researcher found an rs of .89 between amount of blood cholesterol and the severity of the heart attack. Based on an N of 6 and a two-tailed test, the researcher should conclude

not significant

higher blood cholesterol causes more severe heart attacks

significant at the .05 level

p > .05

8. Nonparametric tests are used rather than a t test or an ANOVA when

the assumption of random assignment is not justified

a null hypothesis cannot be specified

the data are in the form of ranks

the researcher does not know the specific value of the population parameters

9. The smallest value of a Spearman rs that is significant at the .05 level for a two-tailed test when the number of pairs is 20 is

.53

.45

.38

.50

10. One common use of statistics in education is to rank a set of universities so the Number 1 is "best" and Number Last is "worst." Suppose you thought that the main variable that determined rank was number of students. Which statistic below should you use to make this comparison?

Chi-Square test

Spearman rs

ANOVA

Paired samples t-test

Reference no: EM132559010

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