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Vs1 = 4V peak1 at 20KHz. Set R5 = 0.
a) Find admittance (Y)as appropriate for each branch.
Use proper engineering notation. For example write 0.000080A as 80uA. Do not forget "w= 2 pi f" when calculating admittances. To help you check your work, the admittance of the third branch that includes L2 is (2.532 - j159.1) umhos.
b) Find the current in each component and total (IT).
To help you check your work, the current in L1 is IL1 =225uA at an angle of -89.54 degrees.
c) Verify Kirchhoff's current law (in = out).
A quick description of R5 is needed before the next calculation can be completed. R5 is called a sampling resistor. R5 is put in series with the power supply so it shares the same current as the circuit. This is the TOTAL current. R5 is selected so it is small enough not to influence the circuit but large enough to generate a voltage that can be measured. Setting R5 equal to 1/20th of the magnitude ZT will allow reasonable measurements without changing the circuit significantly.
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