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The follow data are from a research study comparing two treatment conditions. Use a two-tailed test with ? = .05 to evaluate the mean difference between treatments. For the first test, assume the data are from an independent-measures study using two separate samples. For the second test, assume the data are from a repeated-measures study using the same sample of n = 4 participant in both treatments.treatment 1 treatment 25 1010 74 155 4M = 6 M = 9SS = 22 SS = 66For the repeated-measures test:
TreatmentsI II D D25 10 5 2510 7 - 3 94 15 11 1215 4 -1 1M = 6 M = 9 ?D = 12 ?D2 = 156SS = 22 SS = 66MD = 12/4 = 4 SS = 156 – 122/4 = 156 – 36 = 120 s2 = 120/3 = 40sMD = ?40/4 = ?10 = 3.162 t = 3 – 0 / 3.162 = 3/3.162 = 0.948critical region value = ±3.182Fail to reject the null hypothesis. We conclude there is not a significant difference between treatments.In this example...why is the variance and the standard error larger?
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