Reference no: EM133853999

Question

The wild-type coat color, agouti (AA) is dominant to solid-colored fur (aa). However, a separate gene C, when present as the recessive homozygote (cc), negates any expression of pigment from the A gene and results in an albino mouse. Therefore, the genotypes AAcc, Aacc, and aacc all produce the same albino phenotype. A cross between heterozygotes for both genes (AaCc x AaCc) would generate offspring with a phenotypic ratio of 9 agouti:3 black:4 albino. Which type of gene interaction is this? Group of answer choices Complementary gene interaction Dominant epistasis Dominant gene interaction Duplicate gene interaction Recessive epistasis Flag question: Question 5 Question 51 pts Wild type blue-eyed Mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A dihybrid (WwMm) is self-pollinated. What proportion of the offspring will be magenta?