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The vector position of a 3.80 g particle moving in the XY plane varies in time according to \(r_1= (3i + 3j)t + 2t^2\), where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.15 g particle varies at \(r_2 = 3i - 2it^2 -6jt\)
(a) Determine the vector position of the center of mass at t = 2.90.
(b) Determine the linear momentum of the system at t = 2.90.
(c) Determine the velocity of the center of mass at t = 2.90.
(d) Determine the acceleration of the center of mass at t = 2.90.
(e) Determine the net force exerted on the two-particle system at t = 2.90.
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